Question

A motorcyclist completes one round of a circular track of diameter 280 m in 80 s. What will
be the distance covered and the displacement at the end of 2min 40 seconds?

Answer 1

Answer:

Diameter:- 280m

Radius:- D/2

= 280/2 m

= 140 m

Perimeter of the circular track = 2πr

= 2*22/7*140m

= 880 m

In 80 sec he covers= 880m

In 1 sec he covers= 880/80m

In 2min 40 sec i.e. in 160 sec he covers= 880/80*160 m

= 1760m

Ans:- He covers 1760 metes at the end of 2min 40 seconds..