A motorcyclist covered two-thirds of total journey at his usual speed.he covered the remaining distance ar three-fourth
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let his normal speed be x for y kms
2/3 of y=x
x=2y/3
3x=2y
3x-2y=0 ----------------(1)
y-2/3y=3/4x
3y-2y/3=3x/4
y/3=3x/4
4y=9x
4y-9x=0--------(2)
on solving you will get the answer
2/3 of y=x
x=2y/3
3x=2y
3x-2y=0 ----------------(1)
y-2/3y=3/4x
3y-2y/3=3x/4
y/3=3x/4
4y=9x
4y-9x=0--------(2)
on solving you will get the answer
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