a motorcyclist drive from A to B with a uniform speed of 30 km per hour and return back with a speed of 20 km per hour find the average speed
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Let one way distance be s
t(1)= distance(1)/speed(1)
= S/30h
t(2)= S/ 20h
therefore total time= S/30+S/20
= 5S/60
Hence average speed= total distance /total time, => 2S/ 5S/60
=> 2S ×60/ 5S
=> 120 S/5S
=> 24 km/hr
t(1)= distance(1)/speed(1)
= S/30h
t(2)= S/ 20h
therefore total time= S/30+S/20
= 5S/60
Hence average speed= total distance /total time, => 2S/ 5S/60
=> 2S ×60/ 5S
=> 120 S/5S
=> 24 km/hr
Sinjini4:
okay anything els??
else**
Ya ya, spelling mistake,its else not els #LOL
who writes provide 2 times don't deserve to say this!!
LOL
Still i will pray to god so that you get some sense......बेचारी के अंदर अक्ल की कमी है
ok
Thxx
Welcome ......darling
i u fu****g g**l
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