a motorcyclist drive from A to B with a uniform speed of 30 km/hr and returns from B to A with a uniform speed of 20km/hr.Find it's average speed
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Hi. ..
Let the distance between those two points be d
Speed1 = 30km/h
Time 1 = distance / speed
= d/30 h
Speed while returning = 20km
Time 2 = d/20 h
Average speed = total distance covered / total time taken
=( d+d) ÷ (d/20) +(d/30)
= 2d ÷ (3d+2d) / 60
= (12)(2)
= 24
So, the average speed was 24 km/h...
Hope this helps u!!
Let the distance between those two points be d
Speed1 = 30km/h
Time 1 = distance / speed
= d/30 h
Speed while returning = 20km
Time 2 = d/20 h
Average speed = total distance covered / total time taken
=( d+d) ÷ (d/20) +(d/30)
= 2d ÷ (3d+2d) / 60
= (12)(2)
= 24
So, the average speed was 24 km/h...
Hope this helps u!!
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