a motorcyclist drives from A to B at a uniform speed of 40 km per hour and returns back with a speed of 20 km per hour.Find the average speed.
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Howdy!!
your answer is -------
Let, total distance be 2d
now, from A to B speed is 40km
so, time taken from A to B is
t1 = (d/40)h
now, from B to A speed is 20km
so, time taken from B to A is
t2 = (d/20)h
now, average speed
= total distance / total time
= 2d / t1+t2
= (2d)/(d/20+d/40)
= 2d/(3d/40)
= 80/3 = 26.66 m/s
hope it Help you
your answer is -------
Let, total distance be 2d
now, from A to B speed is 40km
so, time taken from A to B is
t1 = (d/40)h
now, from B to A speed is 20km
so, time taken from B to A is
t2 = (d/20)h
now, average speed
= total distance / total time
= 2d / t1+t2
= (2d)/(d/20+d/40)
= 2d/(3d/40)
= 80/3 = 26.66 m/s
hope it Help you
singhsachin4027:
tnx
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