a motorcyclist drives from A to B with a uniform speed of 30 km h-1 and returns with a speed of 20 km h-1 find its average speed
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Let distance between A and B BE D
HENCE THE
time taken by motorcyclist with uniform speed 30 km/h ,T₁ = distance/speed = D/30 hrs
THERREFORE THEY RETURN AGAIN
they return with uniform speed 20 km , so time taken by motorcyclist , T₂ = D/20 hrs
SO AT THAT MOMENT
average speed of motorcyclist = total distance/total time taken
= (D + D )/(D/30 + D/20) km/h
= 2 × 30 × 20/(30 + 20) km/h
= 24 km/h
Explanation:
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