A motorcyclist drives from A to B with a uniform speed of 20km/hr and returns back with a speed of
5km/hr, the average speed of motorcyclist is the car to rest in
20 s, then the retardation will be:
А.15.1km/hr
B.16km/hr
C.17.5km/hr
D.17.1km/hr
Answers
Answered by
0
Answer:
Correct option is
A
24kmh
−1
Let the length of the line segment AB be x m
The time taken is given as t=distance covered/speed
Total time = t
1
+t
2
=
30
x
+
20
x
=
60
5x
h
Average speed = Total distance/Total time =
5x/60
2x
=24 km/h
Answered by
0
Answer:Let the length of the line segment AB be x m
The time taken is given as t=distance covered/speed
Total time = t
1
+t
2
=
30
x
+
20
x
=
60
5x
h
Average speed = Total distance/Total time =
5x/60
2x
=24 km/h
Explanation:
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