a motorcyclist drives from A to B with uniform speed of 20 km per hour and returns back with speed of 15 km per hour find his average speed
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Let distance covered =X
T¹ = X/20 & T² =X/15
average speed =2X ÷ (X/20 + X/15)
=2X × 60 /7X
=120/7 = 17.14 km per hour
T¹ = X/20 & T² =X/15
average speed =2X ÷ (X/20 + X/15)
=2X × 60 /7X
=120/7 = 17.14 km per hour
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