Question

A motorcyclist drives from place A to B with a uniform speed of 40 km/h and return from place B to A with a uniform speed of 20 km/h.Find its average speed

Answer 1

Hola Mate

Here is your ans

Let,

Total distance from A to B = x

Total Distance from B to A = x

So,

Total Distance covered = 2x

Now,

AVERAGE SPEED = TOTAL DISTANCE COVERED / TOTAL TIME TAKEN

so,

Total distance covered = 2x

Time Taken to move A to B = x/40

Time Taken To cover B to A = x/20

so,

Average speed = 2x/x/40+x/20

2x/3x/40

2x*40/3x

= 80x/3x

80/3km/h

So this is the ans pls mark as brainliest

Answer 2

Explanation:

A to B = Speed =40 km/h

Let Time of A to B = T1(time 1)

Time =Distance/speed

T1=D/40

B to A = Speed = 20 km/h

Let time from B to A =T2 (time2)

Time =Dis/speed

T2=D/20

Average speed=Distance/Time taken

=(D+D)/D/40+D/20

=2D/3D/40

=80/3

=26.6

I hope you will get help from this