Physics, asked by haardik26, 10 months ago

A motorcyclist drives from place A to B with a uniform speed of 30km/h and returns from place B to A with a uniform speed of 20km/h. Find his average speed

Answers

Answered by Anonymous

Answer:

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Let distance between A and B is D

Then, time taken by motorcyclist with uniform speed 30 km/h ,T₁ = distance/speed = D/30 hrs

Again, they return with uniform speed 20 km , so time taken by motorcyclist , T₂ = D/20 hrs

Now, average speed of motorcyclist = total distance/total time taken

= (D + D )/(D/30 + D/20) km/h

= 2 × 30 × 20/(30 + 20) km/h

= 24 km/h

Answered by Anonymous

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Let the length of the line segment AB be x m

The time taken is given as t=distance covered/speed

Total time = t

1 +t 2 =30x + 20

x = 60 5x h

Average speed = Total distance/Total time =

5x/60

2x=24 km/h

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