A motorcyclist drives from place A to B with a uniform speed of 30km per hour and return s from place B to A with a uniform speed of 20 km per hour.what is his average speed.
Answers
Answered by
1
Answer:
25 km/hr
Step-by-step explanation:
avg = (30+20)/2
Answered by
3
Lets suppose the time taken in moving from A to B is T1.
Speed = 30km/hr
So T1= AB/30
Lets suppose the time taken in moving from B to A is T2
Speed = 20 km/hr
T2 = AB/20
Total distance = 2AB
Total Time = AB/20 + AB/30
= AB [1/20 +1/30]
= AB [50/600]
=ABx 5/60
Average Speed = Total Distance / Total Time
= 2ABx60/ABx5 = 120/5 = 24 km/hr
Hope it helps you
please mark me brainliest
Similar questions