a motorcyclist drives from place A to B with a uniform speed of 30km/hr and returns From place B to A with a uniform speed of 20km/hr. find his average speed.
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hey dear here is your answer
1st case:-
given,v=30 km /h
s= x
t1=?
v=s/t1
t1=s/v
t1=x/30 h
2nd case:-
given,v =20 km/h
s=x
t2=?
v=s/t2
t2=s/v
t2=x/20 h
now average speed = total distance / total time taken
=x+x/x/30+x/20
=2x/2x+3x/60
=2x/5x × 60
=24 m/s
hope it helps you. ..
1st case:-
given,v=30 km /h
s= x
t1=?
v=s/t1
t1=s/v
t1=x/30 h
2nd case:-
given,v =20 km/h
s=x
t2=?
v=s/t2
t2=s/v
t2=x/20 h
now average speed = total distance / total time taken
=x+x/x/30+x/20
=2x/2x+3x/60
=2x/5x × 60
=24 m/s
hope it helps you. ..
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