A motorcyclist drives from point a to b with a uniform speed of 30 km/h and return back with a speed of 20 km/h. Find its average speed. Please solve this problem.
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Average speed of the motorcyclist= (20+30)/2
= 25 km/h
Average speed= 25 km/h
MARK IT AS THE BRAINLIEST PLEASE........
= 25 km/h
Average speed= 25 km/h
MARK IT AS THE BRAINLIEST PLEASE........
sauveerdixit:
Mark it as the brainliest please......
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0
(A)●------------------------------------●(B)
Suppose that the body covered the distance from A to BLet the distance between those two points be dSpeed1 = 30km/hTime 1 = distance / speed= d/30 h
Speed while returning = 20kmTime 2 = d/20 h
Average speed = total distance covered / total time taken
=( d+d) ÷ (d/20) +(d/30)= 2d ÷ (3d+2d) / 60= (12)(2)= 24So, the average speed was 24 km/h.
Suppose that the body covered the distance from A to BLet the distance between those two points be dSpeed1 = 30km/hTime 1 = distance / speed= d/30 h
Speed while returning = 20kmTime 2 = d/20 h
Average speed = total distance covered / total time taken
=( d+d) ÷ (d/20) +(d/30)= 2d ÷ (3d+2d) / 60= (12)(2)= 24So, the average speed was 24 km/h.
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