Question

a motorcyclist is moving in a circular path of radius 10m and uniform speed 36km/h.the angel with vertical at which motorcyclist will bend is

Answer 1

heya......

v=36×5/18=10 m/s
r=10m
g=10

so by using formula...

tanФ=v^2/rg

Ф=10^2/10×10

Ф=tan(1)

Ф=45°

hope this will help u


tysm....@gozmit

Answer 2

Hey mate!

Here's your answer!!

Using the formula of bending angle here,

$v = 10m |s \\ \\ \tan( \frac{v {}^{2} }{rg} ) = \frac{100 }{10 \times 10} = 1$
Φ = 45°

Hope it helps you!!!
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