A motorcyclist is moving with a velocity of 40 m/s towards North when it started raining in the absence of wind. If the velocity of rain is 30 m/s then calculate the velocity of the raint and its direction as observed by the motorcyclist.
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Correct option is
B
10
7
ms
−1
Speed of train 108=×
18
5
=30ms
−1
Let
V
ˉ
R
and
V
ˉ
T
represent the respective velocities of rain and train.
Now,the relative velocity of rain w.r.t person (train) is given by v
R,T
=
v
ˉ
R
−
v
ˉ
T
⇒
v
ˉ
R
+(−
v
ˉ
T
)
Let
OR
ˉ
and
RT
ˉ
represent the vectors , respectively in magnitude and direction.
OT
2
=OR
2
+RT
2
+2OR.RTcos120
o
=20
2
+30
2
−2×20×30×
2
1
=400+900−600=700=
700
ms
−1
=10
7
ms
−1
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