Question

a motorcyclist riding motorcycle A is travelling at a speed of 20m/s applied the the brakes and stops the motorcycle in 10s. another motorcyclist of motorcycle B who is travelling at a speed of 5m/s applied the brakes and stops the motorcycle in 20s. plot speed-time graph for the two motorcycle.which of the two motorcycle travelled farther before it come to a stop.

Answer 1

First we will take motorcyclist A-
Initial velocity=20
Final velocity=0
Time=10
Acceleration=final velocity - initial velocity/time
A=0-20/10
A=-2m/s ^2
Now distance travelled in 10 seconds=
S=ut+1/2at^2
S=20x10+1/2x-2x100
S=100m

Now we will take motorcyclist B
Initial velocity=5
Final velocity=0
Time=20
Acceleration=final velocity-initial velocity/time
A=0-5/20
A=-1/4
Now distance travelled in 20 seconds=
S=ut+1/2at^2
S=5x20+1/2x-1/4x400
S=50m

Hence, motorcyclist A travelled more distance than motorcyclist B.

Answer 2

Answer:

Explanation:First we will take motorcyclist A-

Initial velocity=20

Final velocity=0

Time=10

Acceleration=final velocity - initial velocity/time

A=0-20/10

A=-2m/s ^2

Now distance travelled in 10 seconds=

S=ut+1/2at^2

S=20x10+1/2x-2x100

S=100m

Now we will take motorcyclist B

Initial velocity=5

Final velocity=0

Time=20

Acceleration=final velocity-initial velocity/time

A=0-5/20

A=-1/4

Now distance travelled in 20 seconds=

S=ut+1/2at^2

S=5x20+1/2x-1/4x400

S=50m

Hence, motorcyclist A travelled more distance than motorcyclist b

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