Question

a motorcyclist starts from rest and reaches a speed of 6 m/s after travelling with a uniform acceleration for 3 s. what is his acceleration?

Answer 1

Initial V = 0
Final V = 6m/s
Time = 3s

Acceleration = v-u / t
= 6-0 / 3
= 6 / 3
= 2.

Hope this helps!!

Answer 2

initial velocity (u) = 0 (as it starts from rest)
final velocity (v) = 6m/s
tume taken (t) = 3 s

let acceleration be "a"

using 1st equation of motion
v = u + at
6 = 0 + (a)(3)
6 = 3a
a= 2

so, the acceleration was 2m/s^2.