Question

A motorcyclist traveling at 30.7 km/h accelerates after passing a sign post marking the city limits. If it takes 4.9 seconds for the motorcyclist to reach 120 km/h, how far has he traveled past the sign post

Answer 1

initial speed of motorcycle = 30.7 km/h

speed in m/s is given by $v_i = 30.7*\frac{5}{18}$ = 8.53 m/s

final speed of motorcycle = 120 km/h

speed in m/s is given by $v_i = 120*\frac{5}{18}$ = 33.33 m/s

time take to change the speed = 4.9 s

distance traveled by motorcycle

$d = \frac{v_i + v_f}{2}*t$

$d = \frac{33.33 + 8.53}{2}*4.9$

d = 102.55 m

So it will travel a total distance of 102.55 m