Question

a motorcyclists is travelling at a constant velocity of 10m/s in order to overtake a car he accelerates at the rate of 0.2m/s square. if he overtakes the car in 60sec then what is his velocity while overtaking ​

Answer 1

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Answer 2

Given:-

• Initial velocity ,u = 10m/s
• Acceleration ,a = 0.2m/s²
• Time taken ,t = 60s

To Find:-

• Final velocity ,v

Solution:-

According to the Question

We need to calculate the final velocity of the motorcycle .

using 1st equation of motion

• v = u + at

where,

• v is the final velocity
• a is the acceleration
• u is the initial velocity
• t is the time taken

Substitute the value we get

$:\implies$ v = 10 + 0.2 × 60

$:\implies$ v = 10 + 6×2

$:\implies$ v = 10 +12

$:\implies$ v = 22m/s

• Hence, the final velocity of the motorcyclist is 22m/s.