Question

- A motorcyeist riding motorcycle A is
I travelling is a speed of 20m/s applies
the breake and stops the motorcycle
in Jos. Another motorcyclist of motorcycle
I B who is travelling in a speed of
Sunfs applies the breake and stops
the motorcycles in 2015. plot Speed-time
graph for the two no sorcycles, which
of the to two motorcycles teavelled
farther before it cones to a stop d.​

Answer 1

Explanation:

Case I:

For motorist A,

Initial Velocity= u=36km/h=36x5/18=10 m/s

Time=t=10s

by using third equation of motion:

V²-u²=2as

0-10x10=2s(V-u)/t

0-10x10=2s(0-10)/10

-2s=-100s

=100/2=50m

Case II:

For motorist B,

Initial velocity=18km/h=18x5/18=5m/s

time=t=20s

By using third equation of motion:

V²-u²=2as

V²-u²=2s(v-u)/t

0-5x5=2s(0-5)/20-25=-s/2s=50m

so both  A and B cover the same distance.

To draw graph ;we need to find acceleration:

For Motorist A:a=(v-u)/t=(0-10)/10=-1 m/s²

For Motorist B:a=(v-u)/t=(0-5)/20=-0.25 m/s²

Time is from 0 to 20 sec and speed is from 5 to 0.25 m/s

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