Question

A Motorcylist starts from rest and reaches a speed of 6m/sec after traveling with uniform acceleration for 3 sec. What is his acceleration?​

Answer 1

Given

☛ $\:\begin{cases}\sf\red{Initial\: velocity \:(u)\: =\: 0}\\\sf\orange{Final\: velocity\:(v)\:=\:6m/s}\\\sf\blue{Time\:=\:3\: seconds}\end{cases}$

To find

$\bf\blue{Acceleration}$ of the motor cyclist.

Solution

Using 1st equation of motion,

$\Large\star\:{\boxed{\sf{\purple{v\:=\:u\:+\:at}}}}$

Substituting the values,

$\to\:\:\sf{ 6 = 0 + a \times 3}$

$\to\:\:\sf{ 6 = 3a}$

$\to\:\:\sf{ \dfrac{6}{3} = a}$

$\to\:\:\sf{ 2 = a }$

Hence,

• Acceleration of the motor cyclist is $\bf\pink{2m/s^2}$

Additional Information

Few more equations of motion

• $\sf\red{s = ut + \dfrac{1}{2} at^2}$

• $\sf\orange{v^2 = u^2 + 2as}$

• $\sf\purple{s = \dfrac{1}{2}(u + v)t}$

Answer 2

Given :-

• Initial velocity, u = 0
• Final velocity, v = 6 m/s
• Time, t = 3 sec

Need To Find :-

• Acceleration, a =?

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⠀⠀⠀⠀$\underline{\bigstar\:\textsf{Using 1st equation of motion :}}$

$:\implies\sf v = u + at\\\\\\:\implies\sf 6 = 0 + a × 3\\\\\\:\implies\sf 3a=6\\\\\\:\implies\red{\underline{\boxed{\sf a=2\:m/s^2}}}$

⠀

$\therefore\:\underline{\textsf{Acceleration of the motor cyclist is \textbf{2 m/s²}}}.$

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