Question

A motorist covers 200 km of his destination at an average speed of 40 km /hour .Then, he returned to the starting point at an average speed of 50 km/hour. Calculate his average speed for the entire trip.​

Answer 1

time taken to go(t1)=distance/speed

=200/40

=5h

time taken to return=200/50

=4h

Average Velocity= total distance covered/total time taken

=200+200/5+4

=400/9

=44.4 Km/h

Ans.

Answer 2

Average speed for the entire trip is 44.44km/hr.

Step-by-step explanation:

Since we have given that

Average speed for going to his destination = 40 km/hr

Average speed for returning to his starting point = 50 km/hr

Since in both the cases, distance is same.

So, Average speed for the entire trip would be

$\dfrac{2xy}{x+y}\\\\=\dfrac{2\times 40\times 50}{40+50}\\\\=\dfrac{4000}{90}\\\\=\dfrac{400}{9}\\\\=44.44\ km/hr$

Hence, average speed for the entire trip is 44.44km/hr.

# learn more:

Abdul while driving to school as an average speed of 20 km per hour .On his return trip the average speed is 30 km per hour. Find the average speed for his entire trip

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