A motorist is driving at the speed of 60km/hr. A stationary car is 100m
ahead. In how many seconds does he have to stop to avoid a collision?
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Given ;
S = 100 m = 0.1 km
u = 60 km/hr
v = 0
t = ?
v^2-u^2 = 2aS
0-(60×60) = 2×a×0.1
a = -3600/0.2
a = -18000 km/hr
v = u+at
0 = 60+ (-18000)×t
t = 60/18000
t = 1/300 hr
t = (1/300)×60 min
t = 1/5 min
t = 12 sec
S = 100 m = 0.1 km
u = 60 km/hr
v = 0
t = ?
v^2-u^2 = 2aS
0-(60×60) = 2×a×0.1
a = -3600/0.2
a = -18000 km/hr
v = u+at
0 = 60+ (-18000)×t
t = 60/18000
t = 1/300 hr
t = (1/300)×60 min
t = 1/5 min
t = 12 sec
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