a motorist is running at the speed of 72 kilometre per hour sees a danger signal and applies a break the brakes supplier retarding force which is equal to 3 by 4 of the weight of the car find distance covered by the car after the motorist sees the signal if the reaction time of the average motorist is 0.7 second
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Answer:
72 km/h = 20 m/s
Distance = (v * t) + 0.5 * a * t^2
Distance = (20 * 0.7) + 0.5 * a * 0.49
Solving first for a
a = (0 - 20)/0.7
a = - 28.57 m/s^2
Substituting a in the second distance equation above we get distance as 21 m.
The distance traveled by the car after the brakes were applied is 21 meters.
Explanation:
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