Question

A motorist traveling at 70 ms^-1 passes a police man who immediately accelerates to catch the motorist. If the policeman catches the motorist in 16 seconds, what is the policeman's acceleration?

Answer 1

• We are given motorist traveling at speed 70 ms^-1
• We have to find acceleration of police man which we assume to be a ms^-2.
• Now after 16 seconds, he catches the motorist so both must have traveled the same distance.
• Distance traveled by motorist :

        = 70 * 16 m = 1120 m.

• And distance traveled by police man :

         (1/2) * a * (16)^2 which must be equal to 1120 m.

• Solving this equation, we get acceleration of police man a= 8.75 ms^-2.

Answer 2

Answer:

We are given motorist traveling at speed 70 ms^-1

We have to find acceleration of police man which we assume to be a ms^-2.

Now after 16 seconds, he catches the motorist so both must have traveled the same distance.

Distance traveled by motorist :

       = 70 * 16 m = 1120 m.

And distance traveled by police man :

        (1/2) * a * (16)^2 which must be equal to 1120 m.

Solving this equation, we get acceleration of police man a= 8.75 ms^-2.

Explanation: