A motorist travels A to B at a speed of 40km/hr and returns at speed of 60km/hr. His average speed will be?
Answers
Answered by
20
Vavg.= 2v1v2/ v1+v2
Vavg.= 2×40×60/40+60=4800/100=48km/hr
MARK AS BRAIN LEAST.
Vavg.= 2×40×60/40+60=4800/100=48km/hr
MARK AS BRAIN LEAST.
Answered by
5
Answer:
48 km/hr
Explanation:
Av Speed= 2*x/(x/40+x/60)
= 2*60*40/(40+60)
= 48km/hr
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