Question

A mountain climber is sliding down a vertical rope.
Her total mass including the equipments is 65 kg.
By adjusting the friction on the rope, she controls
the tension force on the rope as a function of time
is shown in the fig. The speed of the mountaineer
at the end of 2 sec if she starts from rest is [Take
g= 9.8 ms )
T(N)
637
312
t(sec)
(A) 2.25 ms
(C) 5 ms
(B) 4.5 ms
(D) 2.5 ms​

Answer 1

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2. Homework Equations Fnet=ma trig functions Ff=uFN

3. The Attempt at a Solution

I seperated force into x and y components X --- FN-Tx=0 therefore FN=Tx Y ---- Ff+Ty-mg=0 Ff=uFN=uTx uTx+Ty-mg=0 uTcos78+Tsin78-mg=0