Math, asked by AlkaAnuragi, 8 months ago

A mouse is 20 m away from its burrow and can run at 3m per second. A cat spots the mouse and starts running towards it at 6m per second. (a) How long will it take the mouse to reach its burrow ? (b) If the cat is x meters away from the mouse as shown in the figure , write an expression which tells how long it will take the cat to reach the burrow . (c) If the cat pounces upon the mouse when it is about to enter its burrow, find the value of x. (d) Interpret your result. ​

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Answered by Anonymous
19

Answer:

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Step-by-step explanation:

Distance between mouse and burrow=20 m

Speed of mouse=3 m per sec]

Distance between cat and burrow=(20+x) m

Speed of cat=6 m per sec

Now,

a) Time=Distance/speed of mouse=20/3=6.67 sec

b) Time=Distance/speed of cat⇒t=20+x/6  (here t is time)

c) If cat pounces upon the mouse when it is about to enter the burrow. It means cat also need 6.67 sec to reach the burrow.

So, put t=6.67 or 20/3 sec into result of part (b), we get

t=20+x/6

⇒20/3=20+x/6

⇒3(20+x)=20×6

⇒60+3x=120

⇒3x=120−60

⇒3x=60

⇒x=20

So, the distance between mouse and cat is 20 m.

d) Interpretation of results are done in each part already.Regards.

Answered by khushnoor33
4

(a) time=20/3m

(b) time=20+x/6

(c) 20=3 × 20+x/6

6×20=3(20+x)

120=3(20+x)

120/3=20+x

40=20+x

40-20=x

20m=x

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