Question

A mouse pursued by a cat is 40m ahead of the cat at the start of the chase. While the mouse takes 5 leaps, the cat takes 4. In one leap the mouse goes 1m and the cat goes 2m. Approximately, how far will the mouse have gone when the cat catches the mouse?

Answer 1

At the beginning, the distance between the cat and the mouse is 40 m.

In 1 leap, the mouse covers 1 m
In 1 leap, the cat covers 2 m
Given that, while the mouse takes 5 leaps, the cat takes 4 leaps. ( in the same time )
So in a particular time, the mouse covers 5 m and the cat covers 8 m

By calculating we get, when the cat covers 104 m, the mouse covers 105 m and finally when the mouse covers 110 m, the cat covers 112 m. So at this time the cat catches the mouse. Therefore approximately the mouse would have covered 70 m more when the cat catches it.

Hope this helps you friend
Be brainly ☺☺☺☺☺