A movimng train is stopped by applying brakes. It stops after travelling 80m if the speed of the train is doubled and retardation reemains the same it will cover a distance
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Answered by
1
s=d/t....
double speed =2s
therefore
2s=2(d/t)
distnce covered would be halfed aftr applying brakes
double speed =2s
therefore
2s=2(d/t)
distnce covered would be halfed aftr applying brakes
mohiniteli1980ox70v8:
Not understood how you got 2(d/t)
according to the eqtn
s=d/t
Ans. Is wrong the correct ans is 4times the distance covered earlier
Answered by
1
v² - u² = 2aS
In this case
0 - u² = 2 (-a) S ………[-a because it’s retardation]
S = u² / (2a)
If retardation is kept constant the
S ∝ u²
S₁/S₂ = (u₁/u₂)²
S₂ = S₁ × (u₂/u₁)²
= 80 × (2u₁ / u₁)² ………[∵ speed is doubled => u₂ = 2u₁]
= 80 × 4
= 320 m
If speed is doubled it will cover a distance equal to 320 m
In this case
0 - u² = 2 (-a) S ………[-a because it’s retardation]
S = u² / (2a)
If retardation is kept constant the
S ∝ u²
S₁/S₂ = (u₁/u₂)²
S₂ = S₁ × (u₂/u₁)²
= 80 × (2u₁ / u₁)² ………[∵ speed is doubled => u₂ = 2u₁]
= 80 × 4
= 320 m
If speed is doubled it will cover a distance equal to 320 m
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