a moving ball hits the windscreen of a car and bounces off.which has a greater rate of change of momentum?
Answers
Answered by
0
we know that an action has an equal and opposite reaction.
Let the momentum of ball be p₁=m₁u₁
" "car be p₂=m₂u₂
when there is an equal and opposite reaction, both are equal in magnitude though they act on different bodies.
F=M₁a₁=F₂= m₂a₂
m₁a₁=m₂a₂
therfore m₁(v₁-u₁)/t=m₂(v₂-u₂)/t
m₁v₁-m₁u₁=m₂v₂-m₂u₂
m₂u₂-m₁u₁=m₂v₂-m₁v₁
∴ As rate of change of momentum is equal ,∴ Both have same acceleration and feel the same rate of change of momentum.
Please mark as brainliest
Let the momentum of ball be p₁=m₁u₁
" "car be p₂=m₂u₂
when there is an equal and opposite reaction, both are equal in magnitude though they act on different bodies.
F=M₁a₁=F₂= m₂a₂
m₁a₁=m₂a₂
therfore m₁(v₁-u₁)/t=m₂(v₂-u₂)/t
m₁v₁-m₁u₁=m₂v₂-m₂u₂
m₂u₂-m₁u₁=m₂v₂-m₁v₁
∴ As rate of change of momentum is equal ,∴ Both have same acceleration and feel the same rate of change of momentum.
Please mark as brainliest
Similar questions