Question

A moving ball with a momentum of 25 kg m/s collides head-on with a wall
İt rebounds from the wall with the same speed but in the opposite direction. The time of collision is 50 ms
What is the average force exerted on the wall by the ball during the collision
A 110N
B10N
C1000N

Answer 1

Given :

Initial momentum of the ball = 25 kg-m/s

Time of collison = 50×10⁻³ s

To Find :

The Average force exerted on the wall

Solution :

• As the ball rebounds it travles with same magnitude but of opposite direction

• Final momentum = -25 kg-m/s

• Change in momentum = (initial momentum) - (final momentum)

                                     = 25 -(-25)  = 50kg-m/s

• Force exerted on the wall = Change in momentum / Time of collision

                = 50 / 50×10⁻³ s  

                = 1000N

 The force exerted on the wall is 1000N