A moving bike is brought to rest within 4 second by applying brakes find its initial velocity if it is retardation of 18 km/h^2
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Answer:
v = 0m/s
t = 4s
a = -18km/hr^2
u = ?
1st we have to convert km/hr^2 into m/s^2
-18km/hr^2 * 5/18 = -5m/s
v = u + at
0m/s = u + ( -5m/s^2 ) * 4s
-u = -0 -20m/s
-u = -20m/s
u ( initial velocity ) = 20m/s
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