Question

A moving body is brought to rest in 5 seconds by applying a retarding force of 25N. Calculate change in its momentum.​

Answer 1

Answer:

6s your ans

Explanation:

Retarding force, F=50N

Mass of the body, m=20kg

Initial velocity of the body, u=15m/s

Final velocity of the body, v=0

Using Newtons second law of motion, the acceleration (a) produced is given by:

F=ma

50=20 ×a 

a=−50/20=−2.5m/s2

Using the first equation of motion, the time (t) taken by the body to come at rest

v=u+at

t=−u/a=−15/−2.5=6s

please make me brainlist

I need support for virtuoso rank

Answer 2

Answer:

$\huge\frak\purple{Solution}$

Explanation:

$\sf Retarding \: force, F=50N$

$\sf Mass \: of \: the \: body, m=20kg$

$\sf Initial \: velocity \: of \: the \: \: body, u=15m/s$

$\sf Final \: velocity \: of \: the \: \: body, v=0$

Using Newtons second law of motion, the acceleration (a) produced is given by:

$\sf\red{F=ma}$

$\sf\red{50=20 ×a}$

$\sf\red{a=−50/20=−2.5m/s²}$

Using the first equation of motion, the time (t) taken by the body to come at rest

$\sf\bold{v=u+at}$

$\sf\implies\red{t=−u/a=−15/−2.5=6s}$