Question

A moving body is covering a distance directly proportional to the square of time. The acceleration of the body is
Increasing
Decreasing
Zero

Answer 1

we get equation as x=kt^2 according to given conditions. where k ix a constant.

now differentiate x with respect to time. You will get velocity which will be equal to 2kt.

Now again differentiate this obtained velocity with respect to time. You will get acceleration which will be equal to 2k. Here 2 and k both are constants and so acceleration remains constant.

HOPE THIS HELPS!!