Question

A moving body undergoes an acceleration of 32 m /s^2 starting from rest. Find the distance travelled in 10 sec

Answer 1

Answer:

1600 m

Step-by-step explanation:

Given :

Acceleration ( a ) = 32 $m/sec^2$

Initial velocity ( u ) = 0 m / sec

Time = 10 sec

We have to find distance ( s )

From second equation of motion we have

$\large s=ut+\dfrac{1}{2}at^2$

where  s = distance

a = acceleration

u = Initial velocity

t = time

Now putting values in formula we get

$\large s=0\times10+\dfrac{1}{2}\times32\times10\times10 \\\\\\\large s=0+\dfrac{1}{2}\times32\times10\times10 \\\\\\\large s=16\times10\times10 \\\\\\\large s=16\times100\\\\\\\large s=1600 \ m$

Thus we get answer .