Question

A moving body with a mass mi
strikes a stationary body of mass m2. The masses mi and
mi
m2 should be in the ratio
m2
so as to decrease the velocity of the first body 1.5 times
assuming a perfectly elastic impact. Then the ratio
mi
is
m2​

Answer 1

Answer:

Let initial velocity of mass m

1

be u

1

and its final velocity be v

1

the initial velocity for mass m

2

is zero and let it's final velocity be v

2

,

According to law of conservation of momentum ,

m

1

×u

1

+m

2

×u

2

=m

1

×v

1

+m

2

×v

2

or

m

1

×u

1

=m

1

×v

1

+m

2

×v

2

(since, u

2

=0)

According to the equation for coefficient of restitution for a perfectly elastic collision, we have

v

2

−v

1

=(u

1

)

solving both the equations gives the relation

(m

1

+m

2

)

(m

1

−m

2

)

=

u

1

v

1

=

3

2

Applying componendo and dividendo, we have

m

2

m

1

=

3−2

3+2

=

1

5

m

2

m

1

=5

Answer 2

Answer:

the question is wrong because the mass is 2 be 6 then it is a right question