Question

a moving car decelerates uniformly by 8 m/s squared and come to stop after 6 seconds.
what is the distance traveled during deceleration?

Answer 1

v final velocity =0
u initial velocity =?


v=u+at
0=u+6×-8
0=u-48
48=u

$s = ut + \frac{1}{2} at {}^{2}$

s=288+(-144)
s=144m