A moving car weighing 1200 kg is stopped by applying brakes which produce negative acceleration of 9 ms-2 and it covers 50 m before coming to rest. Calculate amount and type of work done after application of brakes.
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Explanation:
work done = f×s costheta
f= force
s=displacement
W= m × a × s × costheta
W= 1200×9×50× cos(180)
W=6000×9×(-1)
W=54000(-1)
=-54000 J
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