Physics, asked by keshinipriyanka, 3 days ago

A moving coil galvanometer A has 100 turns and resistance 10 ohm. Another galvanometer B has 50 turns and 5 ohm. The other quantities are same in both the cases, Then the voltage sensitivity of
(1) A is great than that of B
(2) B is greater than that of A
(3) A and B are same
(4) Cannot be compared ​

Answers

Answered by sanjaykrishnaamenapp
1

Answer:

Number of turns in coil A NA=100

Resistance of coil A RA=10Ω

Number of turns in coil B NB=50

Resistance of coil B RB=5Ω

Voltage sensitivity of moving coil galvanometer Vs=KRNBA

∴ Vs∝RN (keeping all other quantities to be same)

For coil A : RANA=10100=10

For coil B : RBNB=550=10

⟹ VsA=VsB

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