A moving coil galvanometer allows a full scale current of 10⁻⁴ A. A series resistance of 2 MΩ is required to convert the above galvanometer into a voltmeter of range 0 – 5 V. Therefore the value of shunt resistance required to convert the above galvanometer into a ammeter of range 0–10 mA is:
(A) 200 Ω (B) 100 Ω
(C) 10 Ω (D) 500 Ω
Answers
Answered by
0
Explanation:
I sended 3 pics continue
Attachments:
Answered by
1
The value of resistance of galvanometer is coming is negative which is not possible so none of the options are correct.
Given
1. fullscale current =10⁻⁴A
2. Maximum voltage of voltmeter=5V
3. series resistance=2MΩ
Let the resistance of galvanometer= G
2*10⁶*10⁻⁴+10⁻⁴G=5
200+10⁻⁴G=5
Therefore G=-195*10⁴
therefore we get the value of G =negative
which is not possible so we can take this question as a bonus one
Similar questions