Question

A moving object of mass 80 kg moving with velocity 2 metre per second hand bike collides with another object of mass 20 kg moving with velocity 4 metre per second find the loss of energy assuming a perfectly inelastic collision

Answer 1

hello friend here is ur ans

given :
V1= 2m/s
m1=80kg

V2=4m/s
M2= 20 kg


so therfore the energy of the first object is given by

KE1= 1/2M1(V1)^2

KE1 = 1/2× 80 × (2)^2

KE 1= 40× 4

KE1= 1600 joules========(1)

kinetic energy of second object is given by

KE2= 1/2M2(V2)^2

KE2= 1/2×20×(4)^2

KE2= 10 ×16 = 160 JOULES

KE2 = 160 JOULES ========(2)

SUBTRACTING EQUATION 1 BY 2

GIVES
KE1-KE2 = 1600-160 = 1500 JOULES , SO THERFORE ENERGY LOST IS 160 JOULES

SO I HOPE IT HELPS YOU.

##########BE BRAINLY ##############

Answer 2

Answer:

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