Physics, asked by pallabi3858, 1 year ago

a moving point traverse the distance,s=8t-10t^2 in time t sec. Find the velocity at the instant t=2 sec​

Answers

Answered by Anonymous
2

velocity = ds/dt

ds/dt = 8 - 20t

v at (t = 2 ) = 8 - 20 × 2 = -32 m/s

hope it helps

Answered by jayantbittoo
1

here we are given the function

s(t)=8t-10t^2

s(2)=16-40=-24 m

v=s/t= -24/2=-12 m

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