A moving train crosses a man standing on a platform and the platform 300m long in 10sec and 25 sec respectvely.what will be the time taken by the train to cross a platform 200m long.
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125
Answer:
20 seconds.
Step-by-step explanation:
Train crosses the platform whose length is 300 metres in25−10=15 seconds, here train's length is not added.
So speed of the train =300/15 = 20 m/sec
length of the train = 10×20 = 200 metres
Time taken by the train to cross a platform 200 metre long
=length of train + platform / speed
=(200+200)20=400/20
Time taken by train = 20 seconds.
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Solution :-
Let speed train is x .
Length of train = x × 10 = 10x m-----------1
=> Speed of train = (10x +300)/ 25
=> x = (10x +300)/ 25
=> 25x = 10x +300
=> 15x = 300
=> x = 20 m/s
Length of train =10x = 200m
Time taken by train to cross a platform = (200+200) /20 = 20s
correct answer is 20 second .
______________________________
Solution :-
Let speed train is x .
Length of train = x × 10 = 10x m-----------1
=> Speed of train = (10x +300)/ 25
=> x = (10x +300)/ 25
=> 25x = 10x +300
=> 15x = 300
=> x = 20 m/s
Length of train =10x = 200m
Time taken by train to cross a platform = (200+200) /20 = 20s
correct answer is 20 second .
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