a moving train is brought to rest with in 20 second by playing break if the retardation due to break is 2 metre per second ^2 then the initial velocity was
Answers
Answered by
1
HI FRIEND
______________________________
HERE IS YOUR ANSWER :-
GIVEN :
FINAL VELOCITY (v) = 0 m/s
TIME = 20 SECONDS
RETARDATION = 2 m/s^2
THEREFORE :
RETARDATION =
- (ACCELERATION)
2 = - (ACCELERATION)
ACCELERATION = - 2 m/s^2
ACCELERATION = v - u/t
- 2 = 0 - u/20
- 2 × 20 = -u
- u = - 40
u = 40 m/s
THEREFORE, INITIAL VELOCITY (u) = 40 m/s
______________________________
HOPE IT HELPS
MARK MY ANSWER BRAINLIEST
______________________________
HERE IS YOUR ANSWER :-
GIVEN :
FINAL VELOCITY (v) = 0 m/s
TIME = 20 SECONDS
RETARDATION = 2 m/s^2
THEREFORE :
RETARDATION =
- (ACCELERATION)
2 = - (ACCELERATION)
ACCELERATION = - 2 m/s^2
ACCELERATION = v - u/t
- 2 = 0 - u/20
- 2 × 20 = -u
- u = - 40
u = 40 m/s
THEREFORE, INITIAL VELOCITY (u) = 40 m/s
______________________________
HOPE IT HELPS
MARK MY ANSWER BRAINLIEST
Similar questions