a moving train is brought to rest with in 20 second find initial velocity if the retardation due to breaks 20 m s square
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since the answer will be 40 m per second
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20 *20=400,,,NOT 40
yes I know thanks bro
It's OK
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v=u+at
0=u+(-20)(20)
(becoz retardation = - acceleration)
0= - 400 u
400=u
Initial velocity is 400m/sec
0=u+(-20)(20)
(becoz retardation = - acceleration)
0= - 400 u
400=u
Initial velocity is 400m/sec
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