Question

a moving train is brought to rest within 15 seconds by applying brakes.find the initial velocityof the train if the retardation due to brakes is 3metre per second square and also find the distance travelled by train during the time of retardation.​

Answer 1

v=u+at

0=u+-3×15

u=45m/sec

now distance covered

s=ut+1/2at²

s=45*15+1/2-3×225

s= 45×15 -675/2

s=675-337.5=337.5

Answer 2

Answer:

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