Question

A moving train is brought to rest within 15sec by applying breaks. Find 1)the initial velocity of the train, if the retardation due to break is 3m/s² 2)the distance travelled by train during the time of retardation?

Answer 1

Answer:

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Answer 2

1) the initial velocity of the train will be 45m/s

Explanation:

final velocity of the train will be 0 as it comes to rest after travelling certain distance

therefore, v=0

a= -3m/S2 (given)

time= 15sec (given)

by using the kinemetical equation: v=u+at

we get, 0=u+-3×15

0=u-45

therefore, u=45m/s