Question

a moving train is brought to rest within 20 sec by applying the breaks . find initial velocity if the retardation due to breakes is 1.5 m/s²​

Answer 1

Answer:

30 m/s

Step-by-step explanation:

Retardation = 1.5 m/s^2

Therefore acceleration = a = (-1.5)m/s^2

Initial velocity = u m/s

Final velocity = v = 0m/s [Since the train finally comes to rest]

Time = t = 20 seconds.

ATQ,

v-u/t = a

=>0-u/20 = (-1.5)

=> -u = (-1.5 × 20)

=>-u = -30.0

=> u = 30 m/s