a moving train is brought to rest within 20 seconds by applying brakes . find the initial velocity if the retardation due to brakes is 2m per second^2
Answers
Answered by
6
apply v=u+at
v= final velocity =0 (since train stops)
u= initial velocity =?
a= acceleration= -2 ( since it will stop the train so it will be in opppsite to direction of motion better known as retardation)
t= time =20 sec.
so we get
u = 2x20
= 40 m/sec
Answered by
16
Solution:
Given,
Time, t = 20 s
Retardation, a = -2 m/s^2
Final velocity = 0
Here, retardation means if the speed of a particle or object decreases, we say that it is decelerating or it has a retardation.
By using the formula of acceleration
a = v - u / t
Therefore, v = u + at
=> v = u + at
=> 0 = u + (-2) × 20
=> 0 = u - 2 × 20
=> u = 40 m/s
Therefore, u = 40 m/s
Thus, the initial velocity of train is 40 m/s.
Given,
Time, t = 20 s
Retardation, a = -2 m/s^2
Final velocity = 0
Here, retardation means if the speed of a particle or object decreases, we say that it is decelerating or it has a retardation.
By using the formula of acceleration
a = v - u / t
Therefore, v = u + at
=> v = u + at
=> 0 = u + (-2) × 20
=> 0 = u - 2 × 20
=> u = 40 m/s
Therefore, u = 40 m/s
Thus, the initial velocity of train is 40 m/s.
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